Answer
$\frac{16y^{14}}{x^2}$
Work Step by Step
$(\frac{4x^2y^3}{x^3y^{-4}})^2$
$=\frac{16x^4y^6}{x^6y^{-8}}$
$=16x^{4-6}y^{6-(-8)}$
$=16x^{-2}y^{14}$
$=\frac{16y^{14}}{x^2}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 5 - Test - Page 408: 8
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