Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Test: 8

Answer

$\frac{16y^{14}}{x^2}$

Work Step by Step

$(\frac{4x^2y^3}{x^3y^{-4}})^2$ $=\frac{16x^4y^6}{x^6y^{-8}}$ $=16x^{4-6}y^{6-(-8)}$ $=16x^{-2}y^{14}$ $=\frac{16y^{14}}{x^2}$
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