Answer
$4x^2y^2-6+\frac{2}{x}$
Work Step by Step
$\frac{12x^3y^3-18xy+6y}{3xy}$
$=12x^3y^3(\frac{1}{3xy})-18xy(\frac{1}{3xy})+6y(\frac{1}{3xy})$
$=4x^2y^2-6+\frac{2}{x}$
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