Answer
$x^2y^2-3+\frac{xy}{11}$
Work Step by Step
$\frac{11x^3y^3-33xy+x^2y^2}{11xy}$
$=11x^3y^3(\frac{1}{11xy})-33xy(\frac{1}{11xy})+x^2y^2(\frac{1}{11xy})$
$=x^2y^2-3+\frac{xy}{11}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 5 - Section 5.7 - Dividing Polynomials - Exercise Set - Page 397: 38
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