Answer
Answer:
$4x^{3}-2x^{2}+3x+1$
Work Step by Step
Given: $\frac{8x^{3}-4x^{2}+6x+2}{2}$
= $\frac{(2)4x^{3}-(2)2x^{2}+(2)3x+(2)1}{2}$
This is equal to : $\frac{(2)4x^{3}}{2}$ - $\frac{(2)2x^{2}}{2}$ + $\frac{(2)3x}{2}$ + $\frac{(2)1}{2}$
=$4x^{3}-2x^{2}+3x+1$ .....(Since $\frac{2}{2}=1$ )
