Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.6 - Special Products - Exercise Set: 69

Answer

$\dfrac{1}{9}a^{4}-49$

Work Step by Step

$\Big(\dfrac{1}{3}a^{2}-7\Big)\Big(\dfrac{1}{3}a^{2}+7\Big)$ To evaluate this product, use the following formula: $(x-y)(x+y)=x^{2}-y^{2}$ Here, $x=\dfrac{1}{3}a^{2}$ and $y=7$ $\Big(\dfrac{1}{3}a^{2}-7\Big)\Big(\dfrac{1}{3}a^{2}+7\Big)=\Big(\dfrac{1}{3}a^{2}\Big)^{2}-(7)^{2}=\dfrac{1}{9}a^{4}-49$
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