Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.6 - Integrated Review - Exponents and Operations on Polynomials - Page 390: 17

Answer

$\dfrac{x^{27}}{27}$

Work Step by Step

$(3^{-1}x^{9})^3=(\dfrac{1}{3}x^{9})^3=(\dfrac{x^{9}}{3})^3=\dfrac{x^{9*3}}{3^3}=\dfrac{x^{27}}{27}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.