Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.6 - Integrated Review - Exponents and Operations on Polynomials: 17

Answer

$\dfrac{x^{27}}{27}$

Work Step by Step

$(3^{-1}x^{9})^3=(\dfrac{1}{3}x^{9})^3=(\dfrac{x^{9}}{3})^3=\dfrac{x^{9*3}}{3^3}=\dfrac{x^{27}}{27}$
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