Answer
$(y^{3}-3y^{2}+3y-1)$ meters
Work Step by Step
Step 1: Volume of a cube = $L^{3}$, where L is the length of one side.
Step 2: Since $L=(y-1)$ meters,
Volume= $(y-1)^{3}=(y-1)(y-1)^{2}.$
Step 3: Simplifying, $(y-1)(y^{2}-2y+1)$
Step 4: $y(y^{2}-2y+1)-1(y^{2}-2y+1)$
Step 5: $y^{3}-2y^{2}+y-y^{2}+2y-1$
Step 6: $y^{3}-3y^{2}+3y-1$
Step 7: Therefore, the volume is $(y^{3}-3y^{2}+3y-1)$ meters.
