Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.5 - Multiplying Polynomials - Exercise Set: 24

Answer

$-12b^{5}+48b^{4}+24b^{2}$

Work Step by Step

$-4b^{2}(3b^{3}-12b^{2}-6)=(-4b^{2})(3b^{3})+(-4b^{2})(-12b^{2})+(-4b^{2})(-6)=(-12b^{2+3})+48b^{2+2}+24b^{2}=(-12b^{5})+48b^{4}+24b^{2}=-12b^{5}+48b^{4}+24b^{2}$
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