Answer
$\dfrac{1}{2}m^{2}-\dfrac{7}{10}m+\dfrac{13}{16}$
Work Step by Step
$\Big(\dfrac{3}{4}m^{2}-\dfrac{2}{5}m+\dfrac{1}{8}\Big)+\Big(-\dfrac{1}{4}m^{2}-\dfrac{3}{10}m+\dfrac{11}{16}\Big)$
Remove both parentheses:
$\dfrac{3}{4}m^{2}-\dfrac{2}{5}m+\dfrac{1}{8}-\dfrac{1}{4}m^{2}-\dfrac{3}{10}m+\dfrac{11}{16}=...$
Simplify by combining like terms:
$...=\Big(\dfrac{3}{4}-\dfrac{1}{4}\Big)m^{2}-\Big(\dfrac{2}{5}+\dfrac{3}{10}\Big)m+\Big(\dfrac{1}{8}+\dfrac{11}{16}\Big)=...$
$...=\dfrac{2}{4}m^{2}-\dfrac{20+15}{50}m+\dfrac{16+88}{128}=...$
$...=\dfrac{1}{2}m^{2}-\dfrac{35}{50}m+\dfrac{104}{128}=...$
$...=\dfrac{1}{2}m^{2}-\dfrac{7}{10}m+\dfrac{13}{16}$
