Answer
$\dfrac{3}{20}x^{3}+6x^{2}-\dfrac{13}{20}x-\dfrac{1}{10}$
Work Step by Step
$\dfrac{3}{20}x^{3}+\dfrac{1}{10}-\dfrac{3}{10}x-\dfrac{1}{5}-\dfrac{7}{20}x+6x^{2}$
Simplify the expression by combining like terms:
$\dfrac{3}{20}x^{3}+6x^{2}-\Big(\dfrac{3}{10}+\dfrac{7}{20}\Big)x+\Big(\dfrac{1}{10}-\dfrac{1}{5}\Big)=...$
$...=\dfrac{3}{20}x^{3}+6x^{2}-\Big(\dfrac{60+70}{200}\Big)x+\Big(\dfrac{5-10}{50}\Big)=...$
$...=\dfrac{3}{20}x^{3}+6x^{2}-\dfrac{130}{200}x-\dfrac{5}{50}=...$
$...=\dfrac{3}{20}x^{3}+6x^{2}-\dfrac{13}{20}x-\dfrac{1}{10}$