Answer
$16y^{7}$
Work Step by Step
We know that $a^{−n}=\frac{1}{a^{n}}$ and $\frac{1}{a^{-n}}=a^{n}$ (as long as a is a nonzero real number and n is an integer).
Therefore, $\frac{16}{y^{-7}}=16\times y^{7}=16y^{7}$.
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