Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.2 - Negative Exponents and Scientific Notation - Practice: 9

Answer

$27x^{12}$

Work Step by Step

$\frac{(3x^{5})^{3}x}{x^{4}}=\frac{3^{3}\times(x^{5})^{3}\times x}{x^{4}}=\frac{27\times x^{5\times3}\times x}{x^{4}}=\frac{27\times x^{15}\times x}{x^{4}}=\frac{27x^{15+1}}{x^{4}}=\frac{27x^{16}}{x^{4}}=27x^{16-4}=27x^{12}$
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