Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.1 - Exponents - Practice: 20

Answer

$-8p^{12}q^{6}r^{3}$

Work Step by Step

Based on the power of a product rule, we know that $(ab)^{n}=a^{n}b^{n}$ (where $n$ is a positive integer and $a$ and $b$ are real numbers). Based on the power rule for exponents, we know that $(a^{m})^{n}=a^{mn}$ (where $m$ and $n$ are positive integers and $a$ is a real number). Therefore, $(-2p^{4}q^{2}r)^{3}=(-2)^{3}\times p^{4\times3}\times q^{2\times 3}\times r^{3}=-8p^{12}q^{6}r^{3}$.
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