Answer
$\dfrac{(2x^{6}y^{2})^{5}}{-32x^{20}y^{10}}=-x^{10}$
Work Step by Step
$\dfrac{(2x^{6}y^{2})^{5}}{-32x^{20}y^{10}}$
First, evaluate the exponential expression in the numerator:
$\dfrac{(2x^{6}y^{2})^{5}}{-32x^{20}y^{10}}=\dfrac{32x^{30}y^{10}}{-32x^{20}y^{10}}=...$
Evaluate the division:
$\Big(\dfrac{32}{-32}\Big)x^{30-20}y^{10-10}=-x^{10}y^{0}=-x^{10}$