Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.1 - Exponents - Exercise Set: 105

Answer

$\dfrac{(2a^{5}b^{3})^{4}}{-16a^{20}b^{7}}=-b^{5}$

Work Step by Step

$\dfrac{(2a^{5}b^{3})^{4}}{-16a^{20}b^{7}}$ First, evaluate the exponential expression in the numerator: $\dfrac{(2a^{5}b^{3})^{4}}{-16a^{20}b^{7}}=\dfrac{16a^{20}b^{12}}{-16a^{20}b^{7}}=...$ Now, evaluate the division: $...=\dfrac{16}{-16}a^{20-20}b^{12-7}=-a^{0}b^{5}=-b^{5}$
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