Answer
$\dfrac{(2a^{5}b^{3})^{4}}{-16a^{20}b^{7}}=-b^{5}$
Work Step by Step
$\dfrac{(2a^{5}b^{3})^{4}}{-16a^{20}b^{7}}$
First, evaluate the exponential expression in the numerator:
$\dfrac{(2a^{5}b^{3})^{4}}{-16a^{20}b^{7}}=\dfrac{16a^{20}b^{12}}{-16a^{20}b^{7}}=...$
Now, evaluate the division:
$...=\dfrac{16}{-16}a^{20-20}b^{12-7}=-a^{0}b^{5}=-b^{5}$