Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Section 5.1 - Exponents - Exercise Set: 102

Answer

2

Work Step by Step

Based on the power rule for exponents, we know that $(a^{m})^{n}=a^{mn}$ (where $m$ and $n$ are positive integers and $a$ is a real number). Therefore, $(9^{0})^{4}+(z^{0})^{5}=9^{0\times4}+z^{0\times5}=9^{0}+z^{0}=1+1=2$. Recall that any nonzero real number raised to the power of zero will have a value of 1.
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