Answer
2
Work Step by Step
Based on the power rule for exponents, we know that $(a^{m})^{n}=a^{mn}$ (where $m$ and $n$ are positive integers and $a$ is a real number).
Therefore, $(9^{0})^{4}+(z^{0})^{5}=9^{0\times4}+z^{0\times5}=9^{0}+z^{0}=1+1=2$.
Recall that any nonzero real number raised to the power of zero will have a value of 1.
