Answer
$4a-1+\frac{2}{a^2}-\frac{5}{2a^3}$
Work Step by Step
$\frac{8a^4-2a^3+4a-5}{2a^3}$
$=8a^4(\frac{1}{2a^3})-2a^3(\frac{1}{2a^3})+4a(\frac{1}{2a^3})-5(\frac{1}{2a^3})$
$=4a-1+\frac{2}{a^2}-\frac{5}{2a^3}$
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