Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Review: 140

Answer

$4a-1+\frac{2}{a^2}-\frac{5}{2a^3}$

Work Step by Step

$\frac{8a^4-2a^3+4a-5}{2a^3}$ $=8a^4(\frac{1}{2a^3})-2a^3(\frac{1}{2a^3})+4a(\frac{1}{2a^3})-5(\frac{1}{2a^3})$ $=4a-1+\frac{2}{a^2}-\frac{5}{2a^3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.