Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Review: 129

Answer

$9a^{2}b^{8}$

Work Step by Step

$\frac{a^{-3}b^{6}}{9^{-1}a^{-5}b^{-2}}=$ $\frac{9^{1}a^{-3+5}b^{6+2}}{1}=$ $\frac{9a^{2}b^{8}}{1}=$ $9a^{2}b^{8}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.