Answer
$9a^{2}b^{8}$
Work Step by Step
$\frac{a^{-3}b^{6}}{9^{-1}a^{-5}b^{-2}}=$
$\frac{9^{1}a^{-3+5}b^{6+2}}{1}=$
$\frac{9a^{2}b^{8}}{1}=$
$9a^{2}b^{8}$
Algebra: A Combined Approach (4th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321726391
ISBN 13:
978-0-32172-639-1
Chapter 5 - Review - Page 407: 129
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