Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Review: 127

Answer

$\frac{27a^{12}}{b^{6}}$

Work Step by Step

$(\frac{3a^{4}}{b^{2}})^{3}$=$\frac{(3a^{4})^{3}}{(b^{2})^{3}}$=$\frac{(3)^{3}(a^{4})^{3}}{b^{6}}$=$\frac{27a^{12}}{b^{6}}$
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