Answer
$\frac{1}{7}+\frac{3}{x}+\frac{7}{x^2}$
Work Step by Step
$\frac{x^2+21x+49}{7x^2}$
$=x^2(\frac{1}{7x^2})+21x(\frac{1}{7x^2})+49(\frac{1}{7x^2})$
$=\frac{1}{7}+\frac{3}{x}+\frac{7}{x^2}$
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