Answer
$\frac{9}{4}$
Work Step by Step
$(\frac{-2}{3})^{-2}=\frac{1}{(\frac{-2}{3})^{2}}=\frac{1}{\frac{-2}{3}\times\frac{-2}{3}}=\frac{1}{\frac{4}{9}}=\frac{9}{4}$
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