Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 5 - Review: 23

Answer

$40a^{19}$

Work Step by Step

$5a^{7}(2a^{4})^{3}=5a^{7}\times2^{3}\times(a^{4})^{3}=5a^{7}\times8\times a^{4\times3}=5a^{7}\times8\times a^{12}=5\times8\times a^{7}\times a^{12}=40\times a^{7+12}=40\times a^{19}=40a^{19}$
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