Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Test - Page 330: 8

Answer

The system has no solution since there is no point of intersection.

Work Step by Step

Graph the equations by getting the intercepts and setting arbitrary values for $x$: Equation 1: $y = -3x$ If $x=0$ $$y = -3x$$ $$y = -3(0)$$ $$y=0$$ Hence, we have point (0,0). If $x=1$ $$y = -3x$$ $$y = -3(1)$$ $$y=-3$$ Hence, we have point (1,-3). If $x=-1$ $$y = -3x$$ $$y = -3(-1)$$ $$y=3$$ Hence, we have point (-1,3). Equation 2: $3x + y = 6$ If $x=0$ $$3x + y = 6$$ $$3(0)+ y = 6$$ $$y=6$$ Hence, we have point (0,6). if $y=0$ $$3x + y = 6$$ $$3x+ 0 = 6$$ $$3x = 6$$ $$x=2$$ Hence, we have point (2,0). Graphing these points will give us graphs of two parallel lines. Since there is no point of intersection, therefore the system has no solution.
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