Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Test - Page 330: 5

Answer

FALSE

Work Step by Step

Equation 1: $2x - 3y = 5$ Equation 2: $6x + y = 1$ To determine whether $(1,-1)$ is a solution of the system, we need to evaluate both equations: Equation 1: $$2x - 3y = 5$$ $$2(1) - 3(-1) = 5$$ $$2 + 3 = 5$$ $$5=5$$ $$TRUE$$ Equation 2: $$6x + y = 1$$ $$6(1) + (-1) = 1$$ $$6 -1 = 1$$ $$5=1$$ $$FALSE$$ Since only equation 1 was proved to be true after substituting the given point, therefore point $(1,-1)$ is not a solution of the system.
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