Answer
87 pounds of cheap beans and 113 pounds of high quality beans.
Work Step by Step
First you need to make 2 equations, x+y=200 and 2.65x+4.95y=790. X is the cheap beans, and y is the expensive beans. It equals 200 since that is the total number of pounds of beans, and it is 790 since that is the cost of 200 pounds of normal beans. To solve, I got x by itself so it becomes y=200-x. Plugging in this to the 2nd equation, I got 990-4.95x+2.65x=790. Solving for x, we get 87 pounds, so y must be 113 pounds.
