Answer
($\frac{1}{3}$, 1)
Work Step by Step
Write the first equation as a solution for x:
x = $\frac{1}{2} - \frac{1}{6}y$
Insert the equation for x in terms of y in the second equation:
3($\frac{1}{2} - \frac{1}{6}y$) + 2y = 3
$\frac{3}{2} - \frac{1}{2}y$ + 2y = 3
$\frac{3}{2} + \frac{3}{2}y$ = 3
$\frac{3}{2}y = \frac{3}{2}$
y = 1
Let y = 1 in the first equation to solve for y:
x + ($\frac{1}{6})1 = \frac{1}{2}$
x = $\frac{1}{3}$
Check the solution ($\frac{1}{3}$, 1) in the second equation:
3($\frac{1}{3}$) + 2(1) = 3
1 + 2 = 3
3 = 3; True