Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.2 - Solving Systems of Linear Equations by Substitution - Practice - Page 295: 1

Answer

y = 1 x = 5

Work Step by Step

2x + 3y = 13 ; x = y + 4 Substitute x = y + 4 to the first equation. 2 $\times$ (y + 4) + 3y = 13 2y + 8 + 3y = 13 5y + 8 = 13 5y + 8 - 8 = 13 - 8 5y = 5 y = $\frac{5}{5}$ y = 1 Substitute y = 1 to the second equation x = 1 + 4 x = 5
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