Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 4 - Section 4.1 - Solving Systems of Linear Equations by Graphing - Exercise Set - Page 289: 8

Answer

a. no b.no

Work Step by Step

To find out if an ordered pair is a solution you need to insert the values of the variables into the equation. If the answer of the system is true, the pair is a solution, if not it isn't. a. $4\times0=1-1<=>0=0$ $0-3\times1=-8<=>-3\ne-8$ b.$4\times\frac{1}{6}=1-\frac{1}{3}<=>\frac{2}{3}=\frac{2}{3}$ $\frac{1}{6}-3\times\frac{1}{3}=-8<=>-\frac{5}{6}\ne-8$
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