Answer
(1,-4) is a solution of the system, while (0,6) and (3,0) are not.
Work Step by Step
Equation 1: $2x - y = 6$
Equation 2: $3x + 2y = -5$
Add equation 1 and equation 2:
$$2x - y = 6$$ $$+$$ $$3x + 2y = -5$$ $$=$$ $$5x+y=1$$
The given ordered pairs must satisfy this equation for them to be considered a solution of the system.
$$(1, -4)$$ $$5x+y=1$$ $$5(1)+(-4)=1$$ $$5-4=1$$ $$1=1$$ $$TRUE$$
$$(0, 6)$$ $$5x+y=1$$ $$5(0)+6=1$$ $$0+6=1$$ $$6=1$$ $$FALSE$$
$$(3, 0)$$ $$5x+y=1$$ $$5(3)+0=1$$ $$15=0$$ $$FALSE$$
