Answer
$x+4y=10$
Work Step by Step
$m=-\frac{1}{4}; (2,2)$
$(y-y_1)=m(x-x_1)$
$(y-2)=(-\frac{1}{4})(x-2)$
$y-2=-\frac{1}{4}x+\frac{1}{2}$
$4y-8=-x+2$
$x+4y=10$
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