Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.6 - Graphing Linear Inequalities in Two Variables - Practice - Page 262: 7

Answer

Please see the graph, made using graphing software.

Work Step by Step

$y\geq1/4*x+3$ The y-intercept is $3$, and the slope is $1/4$, and we can use this to draw the line on the graph. $(0,3)$ is on the line (as the y-intercept), and $(4,4)$ is also on the line. (The change in y-values for the slope is 1, and the change in x-values for the slope is 4.) If we add the change in x-values from the slope to the x-value for the y-intercept, we have $4+0 = 4$. If we add the change in y-values from the slope to the y-value for the y-intercept, we have $1 + 3 = 4$. Thus, another point on the line is $(4,4)$. Use $(0,0)$ as a test point to determine what side of the graph to shade. $y\geq1/4*x+3$ $0\geq1/4*0+3$ $0 \geq 0+3$ $0 \geq 3$ is a false statement, so we shade the side of the graph without $(0,0)$.
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