Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set - Page 256: 77

Answer

$$ y=-\frac{1}{3}x-\frac{5}{3}$$

Work Step by Step

$$y = 3x - 1$$ This equation is in the form $y=mx+b$ with $m$ as slobe and $b$ as y-intercept. Since perpendicular lines have opposite slopes (negative reciprocals), then the equation we are looking for will have a slope=$-\frac{1}{3}$. Thus, we have: $$y=-\frac{1}{3}x+b$$ We can now use the given point $(-1, 2)$ to find the y-intercept, $b$. $$y=-\frac{1}{3}x+b$$ $$2=-\frac{1}{3}(-1)+b$$ $$2=\frac{1}{3}+b$$ Subtracting $\frac{1}{3}$ from both sides: $$2-\frac{1}{3}=\frac{1}{3}-\frac{1}{3}+b $$ $$-\frac{5}{3}=b $$ The equation will now become: $$ y=-\frac{1}{3}x-\frac{5}{3}$$ Plotting both equations will give us:
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