Answer
$2x+3y=0$
Work Step by Step
$(0,0)$ and $(-\frac{1}{2},\frac{1}{3})$
$m=\frac{\frac{1}{3}-0}{-\frac{1}{2}-0}=\frac{\frac{1}{3}}{-\frac{1}{2}}=-\frac{2}{3}$
$(y-y_1)=m(x-x_1)$
$(y-0)=-\frac{2}{3}(x-0)$
$y=-\frac{2}{3}x$
$3y=-2x$
$2x+3y=0$