Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.5 - Equations of Lines - Exercise Set - Page 252: 32

Answer

$3x-y=16$

Work Step by Step

$(6,2)$ and $(8,8)$ $m=\frac{8-2}{8-6}=\frac{6}{2}=3$ $(y-y_1)=m(x-x_1)$ $(y-8)=(3)(x-8)$ $y-8=3x-24$ $3x-y=16$
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