Answer
$m_{parallel}=\frac{9}{10}$
$m_{perpendicular}=-\frac{10}{9}$
Work Step by Step
A line parallel to the line that passes through the points (6, -1) and (-4, -10) will have a slope of $m_{parallel}=\frac{-10-(-1)}{-4-(6)}=\frac{-9}{-10}=\frac{9}{10}$
A line perpendicular to the line that passes through the points (-8, -4) and (3, 5) will have a slope of $m_{perpendicular}=-\frac{10}{9}$