## Algebra: A Combined Approach (4th Edition)

$m_{parallel}=\frac{9}{10}$ $m_{perpendicular}=-\frac{10}{9}$
A line parallel to the line that passes through the points (6, -1) and (-4, -10) will have a slope of $m_{parallel}=\frac{-10-(-1)}{-4-(6)}=\frac{-9}{-10}=\frac{9}{10}$ A line perpendicular to the line that passes through the points (-8, -4) and (3, 5) will have a slope of $m_{perpendicular}=-\frac{10}{9}$