Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.2 - Graphing Linear Equations - Exercise Set - Page 212: 28

Answer

Please see the graph.

Work Step by Step

Let $x=0$ $y=\frac{1}{4}x+3$ $y=\frac{1}{4}*0+3$ $y=3$ Let $y=0$ $y=\frac{1}{4}x+3$ $0=\frac{1}{4}*x+3$ $-3=\frac{1}{4}*x$ $-3*4=4*\frac{1}{4}*x$ $-12= x$ Let $x=4$ $y=\frac{1}{4}x+3$ $y=\frac{1}{4}*4+3$ $y=1+3$ $y=4$ Three points on the line are $(0,3), (-12,0),$ and $(4,4)$.
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