## Algebra: A Combined Approach (4th Edition)

Published by Pearson

# Chapter 3 - Section 3.2 - Graphing Linear Equations - Exercise Set: 8

#### Answer

Point A: $y = −5x+2$ $y = −5(0)+2$ $y = 2$ Point B: $y = −5x+2$ $y = −5(1)+2$ $y = −3$ Point C: $y = −5x+2$ $y = −5(2)+2$ $y = −10+2$ $y = -8$

#### Work Step by Step

To get the coordinates of point A, substitute the given x-value of 0 into the given equation $y =−5x+2$ to get the y-value of y=2. Hence, we know that when x is 0, y is 2. i.e (0,2) is a point on the line. To get the coordinates of point B, substitute the given x-value of 1 into the given equation $y =−5x+2$ to get the y-value of y=-3. Hence, we know that when x is 1, y is -3. i.e (1,-3) is a point on the line. To get the coordinates of point C, substitute the given x-value of 2 into the given equation $y =−5x+2$ to get the y-value of y=-8. Hence, we know that when x is 2, y is -8. i.e (2,-8) is a point on the line. Graph points A, B and C using their respective x and y values. Using a ruler, draw a straight line passing through all three points to graph the equation of $y =−5x+2$.

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