Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 3 - Section 3.2 - Graphing Linear Equations - Exercise Set: 3

Answer

Point A: $y=-4x$ $y=-4(1)$ $y=-4$ Point B: $y=-4x$ $y=-4(0)$ $y=0$ Point C: $y=-4x$ $y=-4(-1)$ $y=4$
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Work Step by Step

To get the coordinates of point A, substitute the given x-value of 1 into the given equation $y=-4x$ to get the value of y=-4. Hence, we know that when x is 1, y is -4. i.e (1,-4) is a point on the line. To get the coordinates of point B, substitute the given x-value of 0 into the given equation $y=-4x$ to get the value of y=0. Hence, we know that when x is 0, y is 0. i.e (0,0) is a point on the line. To get the coordinates of point C, substitute the given x-value of -1 into the given equation $y=-4x$ to get the value of y=4. Hence, we know that when x is -1, y is 4. i.e (-1,4) is a point on the line. Find the three points using the x and y values that you found, i.e graph points A, B and C. Using a ruler, draw a straight line passing through all three points to graph the equation of $y=-4x$.
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