Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 2 - Section 2.6 - Percent and Mixture Problem Solving - Exercise Set - Page 162: 52

Answer

3.4

Work Step by Step

1.9 is $100-44=56$% of the average in 1920. Therefore, $\frac{1.9}{56}$ is 1% of the average in 1920. The average in 1920 is $\frac{1.9}{56}*100=3.392$ The nearest tenth is 3.4
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