Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 2 - Section 2.5 - Formulas and Problem Solving - Exercise Set - Page 146: 8

Answer

A = 27

Work Step by Step

Substitute the values for V and h into the equation: V = $\frac{1}{3}$Ah 45 = $\frac{1}{3}$A(5) Solve for A: 45 = $\frac{5}{3}$A $(\frac{3}{5})45 = (\frac{3}{5})\frac{5}{3}$A 27 = A
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