Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 2 - Section 2.5 - Formulas and Problem Solving - Exercise Set - Page 146: 6

Answer

h = 12

Work Step by Step

Substitute the values for A, B, and b into the equation: A = $\frac{1}{2}$h(B + b) 60 = $\frac{1}{2}$h(7 + 3) Solve for h: 60 = $\frac{1}{2}$h(10) 60 = 5h 12 = h
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