Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 2 - Section 2.5 - Formulas and Problem Solving - Exercise Set - Page 146: 3

Answer

h = 3

Work Step by Step

Substitute 102 for S, 7 for l, and 3 for w in the equation: S = 4lw + 2wh 102 = 4(7)(3) + 2(3)h Solve for h: 102 = 84 + 6h 18 = 6h 3 = h
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