Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 2 - Section 2.4 - An Introduction to Problem Solving - Exercise Set - Page 138: 76

Answer

An average eye blinks 720 times per hour, 11520 times in a 16 hour day and 4204800 (365 days) or 4216320 (366 days) times in a year.

Work Step by Step

One minute has 60 seconds so an hour has 60 * 60 = 3600 seconds blinking every five seconds means that you blink $3600\div 5 =720$ times per hour. In 16 hours you blink $16* 720 = 11520$ times. One year has 365/366 days, which means that you are 16 * 365/366 =5840/5856 hours awake. In this time you blink $5840/5856 * 720=4204800/4216320$ times.
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