## Algebra: A Combined Approach (4th Edition)

$y=-\frac{2}{125}(x−50)^2+40$
$y=a(x−h)^2+k$ $y=a(x−50)^2+40$ The point (0,0) represents the end of the bridge. $0=a(0−50)^2+40$ −40=2500a $a=-\frac{2}{125}$ $y=-\frac{2}{125}(x−50)^2+40$