Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 13 - Section 13.1 - The Parabola and the Circle - Exercise Set: 60

Answer

$y=-\frac{2}{125}(x−50)^2+40$

Work Step by Step

$y=a(x−h)^2+k$ $y=a(x−50)^2+40$ The point (0,0) represents the end of the bridge. $0=a(0−50)^2+40$ −40=2500a $a=-\frac{2}{125}$ $y=-\frac{2}{125}(x−50)^2+40$
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