Answer
Vertex = (8, 1)
Work Step by Step
x = -2$y^{2}$ + 4y + 6
x = -2[ $y^{2}$ - 2y - 3 ]
x = -2[ $(y-1)^{2}$ - 1 - 3 ]
x = -2[ $(y-1)^{2}$ - 4 ]
x = -2$(y-1)^{2}$ + 8
Thus vertex = (8, 1)
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