Answer
$-\sqrt[3] {2x}$
Work Step by Step
$-3\sqrt[3] {2x}+\sqrt[3] {16x}$
=$-3\sqrt[3] {2x}+\sqrt[3] {8\times2x}$
=$-3\sqrt[3] {2x}+(\sqrt[3] {8}\times\sqrt[3] {2x})$
=$-3\sqrt[3] {2x}+(2\times\sqrt[3] {2x})$
=$-3\sqrt[3] {2x}+2\sqrt[3] {2x}$
=$-\sqrt[3] {2x}$