Answer
$3x^{3}-4+\frac{1}{x}$
Work Step by Step
Step 1: $\frac{9x^{5}-12x^{2}+3x}{3x^{2}}$
Step 2: $\frac{3x(3x^{4}-4x+1)}{3x^{2}}$
Step 3: $\frac{(3x^{4}-4x+1)}{x}$
Step 4: $\frac{3x^{4}}{x}-\frac{4x}{x}+\frac{1}{x}$
Step 5: $3x^{3}-4+\frac{1}{x}$
