Answer
$-\frac{3y^{4}}{10}$
Work Step by Step
$\frac{-7x^{2}}{5y}\cdot\frac{3y^{5}}{14x^{2}}$
=$\frac{-7x^{2}\times3y^{5}}{5y\times14x^{2}}$
=$\frac{-21x^{2}y^{5}}{70x^{2}y}$
=$-\frac{3x^{2-2}y^{5-1}}{10}$
=$-\frac{3x^{0}y^{4}}{10}$
=$-\frac{3y^{4}}{10}$
