Answer
$\log_{6} 2+\log_{6} x-3\log_{6} y$
Work Step by Step
$\log_{6} \frac{2x}{y^{3}}$
=$\log_{6} 2x-\log_{6} y^{3}$
=$\log_{6} 2+\log_{6} x-\log_{6} y^{3}$
=$\log_{6} 2+\log_{6} x-3\log_{6} y$
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