Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 12 - Section 12.8 - Exponential and Logarithmic Equations and Problem Solving - Practice: 4

Answer

{$\frac{1}{9}$}

Work Step by Step

Step 1: $\log (x+1)-\log x=1$ Step 2: $\log \frac{x+1}{x}=1$ Step 3: $\frac{x+1}{x}=10^{1}$ Step 4: $\frac{x+1}{x}=10$ Step 5: $10x=x+1$ Step 6: $9x=1$ $x=\frac{1}{9}$ Therefore, the solution set is {$\frac{1}{9}$}.
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